Talk:Humanoid Cylon/Archive4

Number of Cylons

Sorry if this is already in the article (I couldn't see a reference to it) but I think there are an equal number of each Cylon model.

Spoilers for season 4, episode 2 follow:

Since there is a deadlock with the vote between the 7 Cylon models, we can infer that there are as many Ones, Fours, and Fives as there are Twos, Sixes, and Eights.

Either there are an equal number of the pro/anti-lobotomy Cylons models _just_ on the baseships concerned with the Raiders (since it would be unlikely for _all_ the Cylons to vote, but this implies that there is a 'rule' against, say, a Six trying to find an equivalent to Boomer on another baseship), or _all_ Cylons voted and there are an equal number the pro/anti models.

I think it's safe to infer that if there are equal numbers of pro/anti models, then there are equal numbers of each Cylon model on each baseship (this implies you can't have 'outside' voters), though I don't think it too much of a stretch to say there are an equal number of Cylon models. FredTheDeadHead 10:58, 28 April 2008 (UTC)

That's not how the voting process works. First they vote within their models to determine the total vote for one model, then that vote is tallied with the votes of the other models. It's not that each individual copy has one vote towards the end result, but only towards the model. The copies can only influence how their model votes in the final vote. Sort of like the US electoral college. -- Serenity 11:08, 28 April 2008 (UTC)

I'm not sure I understand your explanation, and I'm a Limey so I don't understand US politics too well. In 'Six of One' a Cavil says that Boomer has "voted to reconfigure", so each copy has a vote to spend. Do you mean that each copies vote goes toward determining the model's consensus, rather than the decisions? So Boomer's vote would put the Eight's in a state of contention, so they have no vote since there isn't a consensus? FredTheDeadHead 12:50, 28 April 2008 (UTC)